claimroutineinferred_dep

Recurrence solves to O(e^τ) per volume

Recurrence Fk≤(s/W)Fk−1+O(1)F_k\le(s/W)F_{k-1}+O(1) gives O(eτ)O(e^\tau) per volume
solves the swap cost recurrence
Claim·§4.2 Transferring a finite circuit to address permutations·inside propPower-width chunk interchange in O(Ve^τ)

Statement (paper)

Let FkF_k be a uniform upper bound for time divided by logical volume for the interchange of two chunks of e=mke=m^k radix-qq digits each, so that F0=O(1)F_0=O(1) and Fk≤(s/W)Fk−1+O(1)F_k\le(s/W)F_{k-1}+O(1). Since s/W<mτs/W<m^\tau, it follows that Fk=O(mkτ)=O(eτ)F_k=O(m^{k\tau})=O(e^\tau), with the implied constant independent of kk and of all field lengths.

In plain English

If FkF_k is the worst-case ratio of time to logical volume for interchanging two chunks of e=mke=m^k radix-qq digits, then F0=O(1)F_0=O(1) and Fk≤(s/W)Fk−1+O(1)F_k\le(s/W)F_{k-1}+O(1). Because s/W<mτs/W<m^\tau, this gives Fk=O(mkτ)=O(eτ)F_k=O(m^{k\tau})=O(e^\tau) with a constant independent of kk and the field lengths.

Why it's here

The three-shear swap reduces one interchange at level kk to circuit-driven shears whose recursive calls, after dividing by volume, contribute a factor s/Ws/W times the level-(k−1)(k-1) cost plus linear overhead. Since s/W<mτs/W<m^\tau, the geometric recurrence grows at most like mkτm^{k\tau}, which yields the O(Veτ)O(Ve^\tau) time bound claimed in the proposition once the fixed-tape schedule cost per node is accounted for.
Classified routine:
Unrolling the linear recurrence Fk≤(s/W)Fk−1+O(1)F_k\le(s/W)F_{k-1}+O(1) with ratio s/W<mτs/W<m^\tau gives a geometric sum bounded by O(mkτ)O(m^{k\tau}). This is a standard recurrence calculation that uses the shear decomposition from the previous claim.

Sources

PaperOpen
Section
§4.2 Transferring a finite circuit to address permutations
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sections/04-swap.tex:197
Leannot aligned

Phase 2 aligns this node to a Lean declaration.

Friction

  • info
    inferred_dep
    outline: "Volume-normalized recurrence gives O(e^τ)" rests on claim-prop-power-interchange-3